Answer: 42.9%
Step-by-step explanation:
From the given table , the number of part-time jobs =6+8 = 14
Total jobs = 6+8+9+2=25
Let A be the event of selecting a part time job , then
[tex]P(A)=\frac{14}{25}[/tex]
Let B be the event of selecting a job where experience is needed.
The number of part time job openings where experience is needed = [tex]A\cap B=6[/tex]
Then, [tex]P(A\cap B)=\frac{6}{25}[/tex]
Now, the probability that experience is needed for a randomly selected job opening, given that it is for part-time work is given by :-
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\=\dfrac{\dfrac{6}{25}}{\dfrac{14}{25}}\\\\\\=\dfrac{6}{14}=0.428571428571[/tex]
In percent, [tex]P(B|A)=0.428571428571\times100=42.8571428571\%\approx42.9\%[/tex]