For this case we must find the area of the figure shown.
By definition, the area of a triangle is given by:
[tex]A_ {t} = \frac {b * h} {2}[/tex]
The area of a rectangle is given by:
[tex]A_ {r} = a * b[/tex]
Thus, the total area is:
[tex]A = 2 * A_ {t} + A_ {r}[/tex]
Triangle area:
[tex]b = 5 \ cm\\h = 4 \ cm\\A_ {t} = \frac {5 * 4} {2} = 10 \ cm ^ 2[/tex]
Area of the rectangle:
[tex]a = 9 \ cm\\b = 4 \ cm\\A_ {r} = a * b = 9 * 4 = 36 \ cm ^ 2[/tex]
So:
[tex]A = 2 * A_ {t} + A_ {r}\\A = 2 * 10 + 36\\A = 20 + 36\\A = 56 \ cm ^ 2[/tex]
Answer:
Option D
