Answer:
14,700 N
Explanation:
The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:
[tex]W-N=0[/tex] (1)
the weight of the hyppo is
[tex]W=mg=(1500 kg)(9.8 m/s^2)=14,700 N[/tex]
where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find
[tex]N=W=14,700 N[/tex]
