Respuesta :
Answer:
- Option A. n = 6 to n = 1
Explanation:
Niels Bohr was a Danish physicist who proposed the hydrogen atom quantum model to explain the discontinuity of the atom's emission spectra.
In Bohr hydrogen atom model, the electrons occupy orbits identified with the numbers n = 1, 2, 3, 4, ... Each number (orbit) corresponds to a different energy level or state. The number n = 1 corresponds to the lowest energy level, and each higher number corresponds to a higher energy level.
This table shows the relative energy of the different orbits of the Bhor hydrogen atom:
Orbit Quantum Energy Relative
number level energy
First n = 1 1 E₁
Second n = 2 2 2E₁
Third n = 3 3 9E₁
Fourth n = 4 4 16E₁
Fifth n = 5 5 25E₁
Sixth n = 6 6 36E₁
Seventh n = 7 7 49E₁
When an electron jumps from a higher energy state down to a lower energy state, it emits a photon with an energy equal to the difference of the energies between the initial and the final states.
Since the n = 6 to n = 1 transition results in the higher relative energy difference (36E₁ - E₁ = 35E₁), you conclude that it is this transition which results in the emission of the highest-energy photon, which is the option A.
n=6 to n=1 transition results in the emission of the highest-energy photon.
- Emission of protons often goes from a higher energy level down to a lower energy level.
- Bohr shows the hydrogen atom looking at an electron, often moves in a circular orbit in a nucleus. These transitions in the orbits brings about in the absorption or emission of photons.
- When an electron moves from a higher-energy orbit to a more stable one, energy is given off in the form of a photon.
Conclusively we can therefore say that the answer is option A because the n=1 energy level is at the ground state energy level, which therefore implies that energy is the greatest in this energy level
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