The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.

Answer: first option.
Step-by-step explanation:
The ratio of the area of the triangles can be calculated as following:
[tex]ratio_{(area)}=(\frac{l_1}{l_2})^2[/tex]
Where [tex]l_1[/tex] is the lenght of the given side of the smaller triangle and [tex]l_2[/tex] is the lenght of the given side of the larger triangle.
Therefore:
[tex]ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}[/tex]
It can be written as following:
[tex]ratio_{(area)}=49:64[/tex]
The ratio of the perimeter is:
[tex]ratio_{(perimeter)}=\frac{l_1}{l_2}[/tex]
Where [tex]l_1[/tex] is the lenght of the given side of the smaller triangle and [tex]l_2[/tex] is the lenght of the given side of the larger triangle.
Therefore:
[tex]ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}[/tex]
It can be written as following:
[tex]ratio_{(perimeter)}=7:8[/tex]