The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.

The figures are similar Give the ratio of the perimeters and the ratio of the areas of the first figure to the second class=

Respuesta :

Answer: first option.

Step-by-step explanation:

The ratio of the area of the triangles can be calculated as following:

[tex]ratio_{(area)}=(\frac{l_1}{l_2})^2[/tex]

Where [tex]l_1[/tex] is the lenght of the given side of the smaller triangle and [tex]l_2[/tex] is the lenght of the given side of the larger triangle.

Therefore:

[tex]ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}[/tex]

It can be written as following:

[tex]ratio_{(area)}=49:64[/tex]

The ratio of the perimeter is:

[tex]ratio_{(perimeter)}=\frac{l_1}{l_2}[/tex]

Where [tex]l_1[/tex] is the lenght of the given side of the smaller triangle and [tex]l_2[/tex] is the lenght of the given side of the larger triangle.

Therefore:

[tex]ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}[/tex]

It can be written as following:

[tex]ratio_{(perimeter)}=7:8[/tex]