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A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

1 over 4096
1 over 512
1 over 64
1 over 8

Respuesta :

bhavya2vemuri

Answer:

1/152

Step-by-step explanation:

this is because each bead has an 1/8 chance of being picked and there are 3  different colored beads and tamy picks the beads 3 times so 1/8*1/8*1/8=1*152

The probability should be 1 over 512

Given information:

A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times.

Calculation of probability:

[tex]= \frac{1}{8} \times \frac{1}{8} \times \frac{1}{8}\\\\= \frac{1}{512}[/tex]

Hence, the probability should be 1 over 512

Learn more about the probability here: https://brainly.com/question/24442276

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