Answer:
25.11 g.
Explanation:
- It is clear from the balanced equation:
Ag₂O + 2HCl → 2AgCl + H₂O.
that 1.0 mole of Ag₂O reacts with 2.0 moles of HCl to produce 2.0 mole of AgCl and 1.0 moles of H₂O.
- 7.8 g of HCl reacts with excess Ag₂O. To calculate the no. of grams of Ag₂O that reacted, we should calculate the no. of moles of HCl:
no. of moles of HCl = mass/atomic mass = (7.9 g)/(36.46 g/mol) = 0.2167 mol.
- From the balanced equation; every 1.0 mol of Ag₂O reacts with 2 moles of HCl.
∴ 0.2167 mol of HCl will react with (0.2617 mol / 2 = 0.1083 mol) of Ag₂O.
∴ The mass of reacted Ag₂O = no. of moles x molar mass = (0.1083 mol)(231.735 g/mol) = 25.11 g.
