Answer:
Option d- 2 sin2x - 2 sin x cos x - 1
Step-by-step explanation:
the trigonometry identities are useful in this case.
Let the identity be:
Sin 2x = 2 sinx cosx
Cos 2x = 2cos²x - 1
Substituting gives:
2 sinx cosx - (2cos²x - 1)
cosx (2sin x - cosx) + 1
solving gives:
2 sin2x - 2 sin x cos x - 1
