Respuesta :

Answer:

B) 3.10*10^-8 m

Explanation:

The energy of a photon is given by:

[tex]E=\frac{hc}{\lambda}[/tex]

where

[tex]h=6.63\cdot 10^{-34}Js[/tex] is the Planck constant

[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light

[tex]\lambda[/tex] is the photon's wavelength

In this problem, we know the energy of the photon

[tex]E=6.33\cdot 10^{-18} J[/tex]

So we can rearrange the equation to find the wavelength:

[tex]\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{6.33\cdot 10^{-18} J}=3.1\cdot 10^{-8} m[/tex]

The wavelength of a photon that has an energy of 6.33*10^-18 J is 3.1 × 10⁻⁸ m. The correct option is B) 3.10*10^-8

To determine the wavelength of a photon that has an energy of 6.33*10^-18 J (6.33×10⁻¹⁸ J)

We will consider the equation for energy of a photon.

The energy, E, of a photon is given by

[tex]E = h\nu[/tex]

Where [tex]h[/tex] is the Planck's constant (h = 6.626 × 10⁻³⁴Js)

and [tex]\nu[/tex] is the frequency

Recall that,

[tex]\nu =\frac{c}{\lambda}[/tex]

Where c is the speed of light (c = 3.0 × 10⁸ m/s)

and λ is the wavelength

Therefore,

[tex]E = \frac{hc}{\lambda}[/tex]

Since, we are to determine the wavelength, we can write that

[tex]\lambda = \frac{hc}{E}[/tex]

From the question,

E = 6.33×10⁻¹⁸ J

Putting the parameters into the equation, we get

[tex]\lambda = \frac{6.626\times10^{-34} \times 3.0\times 10^{8} }{6.33\times 10^{-18} }[/tex]

[tex]\lambda = \frac{19.878\times10^{-26} }{6.33\times 10^{-18} }[/tex]

[tex]\lambda = 3.14 \times 10^{-26+18}[/tex]

[tex]\lambda = 3.14 \times 10^{-8}[/tex] m ≅ 3.1 × 10⁻⁸ m

Hence, the wavelength of a photon that has an energy of 6.33*10^-18 J is 3.1 × 10⁻⁸ m. The correct option is B) 3.10*10^-8

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