Respuesta :
Answer:
B) 3.10*10^-8 m
Explanation:
The energy of a photon is given by:
[tex]E=\frac{hc}{\lambda}[/tex]
where
[tex]h=6.63\cdot 10^{-34}Js[/tex] is the Planck constant
[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light
[tex]\lambda[/tex] is the photon's wavelength
In this problem, we know the energy of the photon
[tex]E=6.33\cdot 10^{-18} J[/tex]
So we can rearrange the equation to find the wavelength:
[tex]\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{6.33\cdot 10^{-18} J}=3.1\cdot 10^{-8} m[/tex]
The wavelength of a photon that has an energy of 6.33*10^-18 J is 3.1 × 10⁻⁸ m. The correct option is B) 3.10*10^-8
To determine the wavelength of a photon that has an energy of 6.33*10^-18 J (6.33×10⁻¹⁸ J)
We will consider the equation for energy of a photon.
The energy, E, of a photon is given by
[tex]E = h\nu[/tex]
Where [tex]h[/tex] is the Planck's constant (h = 6.626 × 10⁻³⁴Js)
and [tex]\nu[/tex] is the frequency
Recall that,
[tex]\nu =\frac{c}{\lambda}[/tex]
Where c is the speed of light (c = 3.0 × 10⁸ m/s)
and λ is the wavelength
Therefore,
[tex]E = \frac{hc}{\lambda}[/tex]
Since, we are to determine the wavelength, we can write that
[tex]\lambda = \frac{hc}{E}[/tex]
From the question,
E = 6.33×10⁻¹⁸ J
Putting the parameters into the equation, we get
[tex]\lambda = \frac{6.626\times10^{-34} \times 3.0\times 10^{8} }{6.33\times 10^{-18} }[/tex]
[tex]\lambda = \frac{19.878\times10^{-26} }{6.33\times 10^{-18} }[/tex]
[tex]\lambda = 3.14 \times 10^{-26+18}[/tex]
[tex]\lambda = 3.14 \times 10^{-8}[/tex] m ≅ 3.1 × 10⁻⁸ m
Hence, the wavelength of a photon that has an energy of 6.33*10^-18 J is 3.1 × 10⁻⁸ m. The correct option is B) 3.10*10^-8
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