[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{6\times 6}{36}\\ V=48 \end{cases}\implies 48=\cfrac{1}{3}(36)h\implies 48=12h \\\\\\ \cfrac{48}{12}=h\implies 4=h[/tex]
Answer:
Height of the pyramid is:
4 units
Step-by-step explanation:
Here we are given a right rectangular pyramid
Whose Volume is given by:
[tex]V=\dfrac{lwh}{3}[/tex]
where l and w is the length and width of its base and h is the height of the pyramid
Here, we are given l=b=6 units
We have to find h
[tex]V=\dfrac{6\times 6\times h}{3}\\ \\48=6\times 2\times h\\\\48=12\times h\\\\h=4[/tex]
Hence, height of the pyramid is:
4 units
