Answer:
2 NaAlH₄ (s) → 2 NaH (s) + 2 Al (s) + 3 H₂(g)
Explanation:
Decomposition reaction -
It is the type of reaction , where one only one reactant and more than one products ,
As, the reactant breaks down into two or more than products , the reaction me use some sort of catalyst or with the aid of heat and light to proceed , is known as a decomposition reaction .
The decomposition of NaAlH₄ , can be done in the following manner -
generating , NaH and Al as the solid product and H₂ as the gaseous product,
NaAlH₄ (s) → NaH (s) + Al (s) + H₂(g)
The reaction can be balanced , simply by equalizing in the number of atoms in the reactant with the number of atoms in the product side , by multiplying the molecule with whole numbers .
Hence , the balanced reaction is given as -
2 NaAlH₄ (s) → 2 NaH (s) + 2 Al (s) + 3 H₂(g)
The balanced equation for the decomposition of NaAlH4 would be:
[tex]2 NaAlH_4 --->2 NaH + 2 Al + 3 H_2[/tex]
Sodium alanate, NaAlH4 decomposes under specific conditions to produce aluminum, hydrogen gas, and sodium hydride.
For every 1 mole of NaAlH4 that decomposes, 1 mole of sodium hydride, 1 mole of aluminum, and 1.5 moles of hydrogen gas are produced.
Thus, for a balanced equation, 2 moles of NaAlH4 would produce 2 moles of sodium hydride, 2 moles of aluminum, and 3 moles of hydrogen gas.
More on decomposition reaction can be found here: https://brainly.com/question/24936069
