Answer:
The following as a single sine function of an angle:
[tex]12 sin3\theta \cos3\theta cos 6\theta =3\times \sin12\theta [/tex]
Step-by-step explanation:
Given : [tex]12 sin3\theta \cos3\theta cos 6\theta [/tex]
Using identity:
[tex]Sin2x=2\times \sin x \cos x[/tex]
[tex]=6\times 2\times sin3\theta \cos3\theta \cos 6\theta [/tex]
[tex]=6\times (2\times sin3\theta \cos3\theta) \cos 6\theta [/tex]
[tex]=6\times \sin 6\theta \cos 6\theta [/tex]
[tex]=3\times (2\times \sin 6\theta \cos 6\theta) [/tex]
[tex]=3\times \sin12\theta [/tex]
The following as a single sine function of an angle:
[tex]12 sin3\theta \cos3\theta cos 6\theta =3\times \sin12\theta [/tex]
