Respuesta :
Answer with explanation:
Mean of the data set[tex]\mu[/tex] = 112
Standard Deviation of the data set[tex]\sigma[/tex] =2.5
Since , 50% of data lies on both side of the mean.
Z at 50% = 0.1915
Margin of error for this data set
[tex]=Z_{50 \text{percent}}\times\frac{\sigma}{\sqrt{\mu}}\\\\=0.1915 \times \frac{2.5}{\sqrt{112}}\\\\=0.1915 \times \frac{2.5}{10.58}\\\\=0.1915 \times 0.2362\\\\=0.0452[/tex]
Margin of error=0.045(approx)
Answer:
The margin of error for this data set is option B )5
Step-by-step explanation:
Given that a data set has a mean of 112 and a std deviation of 2.5
Since confidence interval level is not given, we can take it as 95% normally used much in finding margin of errors.
For 95% confidence interval, Z critical value is 1.96 or approximately 2.
Margin of error = Z critical * std deviation
= 2(2.5)
=5
Hence option B would b the right answer
The margin of error for this data set is option B )5
