Answer:
Thus, the area of the triangle ABC is 49.5 square units.
Step-by-step explanation:
It is given that in a triangle ABC, the measure of the side AC is 13 and the measure of the side BC is 15 and the measure of the angle C is 30.5.
Thus, the area of the triangle ABC is given as:
[tex]A={\frac{1}{2}}{\times}AC{\times}BC{\times}sin(30.5)[/tex]
Substituting the given values, we have
[tex]A={\frac{1}{2}}{\times}13{\times}15{\times}(0.507)[/tex]
[tex]A={\frac{98.96}{2}}[/tex]
[tex]A=49.5 units^2[/tex]
Thus, the area of the triangle ABC is 49.5 square units.
