Identify the equation in point slope form for the line perpendicular to y= -1/3x-6 that passes through (-1,5).

Answer:
A. y - 5 = 3(x + 1)
Step-by-step explanation:
y = -1/3 x - 6
This line, slope = -1/3
Perpendicular lines, slope is opposite and reciprocal, so slope = 3
Equation that passes thru (-1,5)
y - 5 = 3(x + 1)
For this case we have that if two lines are perpendicular, then it follows that:
[tex]m_ {1} * m_ {2} = - 1[/tex]
We have [tex]m_ {1} = - \frac {1} {3}[/tex]
So:
[tex]- \frac {1} {3} * m_ {2} = - 1\\m_ {2} = \frac {-1} {- \frac {1} {3}}\\m_ {2} = 3[/tex]
Then, the equation is of the form:
[tex]y-y_ {0} = m (x-x_ {0})[/tex]
We have the point:
[tex](x_ {0}, y_ {0}) = (- 1,5)[/tex]
We replace:
[tex]y-5 = 3 (x - (- 1))\\y-5 = 3 (x + 1)[/tex]
ANswer:
[tex]y-5 = 3 (x + 1)[/tex]
Option A