Respuesta :
ANSWER
[tex]C_{2010} - C_{2005} = 5 {x}^{2}+ 10x + 1[/tex]
EXPLANATION
The average cost equation in the year 2005 is:
[tex]C_{2005}
= - 15 {x}^{2} + 20x - 3[/tex]
The average cost equation in the year 2010 is
[tex]C_{2010}
= - 10 {x}^{2} + 30x - 2[/tex]
The difference in average cost equation for cars between 2005 and 2010 is
[tex]C_{2010} - C_{2005} = - 10 {x}^{2} + 30x - 2 - ( - 15 {x}^{2} + 20x - 3)[/tex]
[tex]C_{2010} - C_{2005} = - 10 {x}^{2} + 30x - 2 + 15 {x}^{2} - 20x + 3[/tex]
We regroup the terms to get,
[tex]C_{2010} - C_{2005} = - 10 {x}^{2} + 15 {x}^{2}+ 30x - 20x + 3 - 2[/tex]
Combine the similar terms to
[tex]C_{2010} - C_{2005} = 5 {x}^{2}+ 10x + 1[/tex]
Answer:
Thank you kudzordzifrancis
Step-by-step explanation: His answer is right! Sorry I need the points for an exam I don't understand. :(