Answer: Sherrie must walk 9 more laps.
Step-by-step explanation:
You know that one lap around the school track is [tex]\frac{1}{4}mile[/tex] or 0.25 miles.
Let be [tex]d_1[/tex] the distance in miles that Sherrie walks in 5 laps.
To calculate [tex]d_1[/tex] you need to multiply 0.25 miles by 5. Then:
[tex]d_1=(0.25miles)(5)\\d_1=1.25miles[/tex]
Let be [tex]d_2[/tex] the distance left that Sherrie must walk to reach a total distance of 3.5 miles.
To calculate [tex]d_2[/tex] you need to subtract 3.5 miles and 1.25 miles. Then:
[tex]d_2=3.5miles-1.25miles\\d_2=2.25miles[/tex]
Let be [tex]x[/tex] the number of more laps that she must walk to reach a total distance of 3.5 miles.
If she needs to walk 2.25 miles more to reach a total distance of 3.5 miles and 1 lap is 0.25 miles, then "x" is:
[tex]x=\frac{2.25miles}{0.25miles}\\\\x=9[/tex]
She must walk 9 more laps.
Answer:
EWWW QRONG AWNSER I GOT IT WRONG BRU
:/
Step-by-step explanation:
