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If you have a 90 V power source with a 30-Ω and 60-Ω resistor in series, what is the voltage drop over the 60-Ω resistor?

30 V
2 V
60 V
90 V

Respuesta :

Answer:

= 60 V

Explanation:

Total resistance = 30 Ω+ 60 Ω

                           = 90 Ω

Voltage = 90 V

We can calculate current through the circuit.

I = V/R

 = 90 v/90Ω

 = 1 A

Since the resistors are in series arrangement, then the current through both resistors are the same.

Current through 60Ω resistor is 1 A

Therefore; V = IR

                     = 1 A× 60 Ω

                     = 60 V

Therefore;  the voltage drop over the 60-Ω resistor is 60 V

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