Answer:
[tex](\frac{1}{5})(\frac{1}{4})(\frac{1}{3})[/tex]
Step-by-step explanation:
First digit can be anything from 1 to 5 (5 numbers). What is the probability of getting a "1" in the first digit? It is [tex]\frac{1}{5}[/tex].
Second digit can be anything from 2 to 5 (since 1 already in first digit place). What is the probability of getting a "2" in the 2nd digit? It is [tex]\frac{1}{4}[/tex]
Third digit can be anything from 3 to 5 (since 1 and 2 already in first and second digit, respectively). What is the probability of getting a "3" in the 3rd digit? It is [tex]\frac{1}{3}[/tex].
The second answer choice is right.
