Solve system of equations using multiplication with addition method.

Answer:
(- 1, 5)
Step-by-step explanation:
Given the 2 equations
[tex]\frac{1}{3}[/tex](2x + y) = 1 → (1)
x + y = 4 → (2)
Multiply (1) by 3 to eliminate the fraction
2x + y = 3 → (3)
Eliminate y by subtracting (2) from (3) term by term
(2x - x) + (y - y) = (3 - 4) ← simplify
x = - 1
Substitute x = - 1 into (2) for corresponding value of y
- 1 + y = 4 ( add 1 to both sides )
y = 5
Solution is (- 1, 5)