Respuesta :
Answer:
a) 0.46; b) 0.41; c) 0.19; d) 0.59
Step-by-step explanation:
For part a,
There were 121 people that walked by; out of these 56 entered the store. This is an empirical probability of
56/121 ≈ 0.46
For part b,
There were 56 people that entered the store. Of those, 23 bought something. This is an empirical probability of
23/56 ≈ 0.41.
For part c,
We multiply the probability that someone walking by enters the store and the probability that someone entering the store buys something:
0.46(0.41) = 0.1886 ≈ 0.19
For part d,
Since the probability of someone entering the store buying something is 0.41, this means the probability that this person does not buy something is
1-0.41 = 0.59.
a) The probability that a person who walks by the store will enter the store is 0.46
b) The probability that a person who walks into the store will buy something is 0.41
c) The probability that a person who walks by the store will come in and buy something is 0.19
d) The probability that a person who comes into the store will buy nothing is 0.59
Calculation of the probabilities:
(a)
Since there were 121 people that walked by; out of these 56 entered the store. So this represents the empirical probability
[tex]= 56\div 121[/tex]
≈ 0.46
(b)
Since there were 56 people that entered the store. Of those, 23 bought something.
So, the probability is
[tex]= 23\div 56[/tex]
≈ 0.41.
(c)
The probability should be
= 0.46(0.41)
= 0.1886
≈ 0.19
(d) The probability should be
= 1-0.41
= 0.59.
learn more about the probability here: https://brainly.com/question/5680312