John runs a computer software store. Yesterday he counted 121 people who walked by the store, 56 of whom came into the store. Of the 56, only 23 bought something in the store. (Round your answers to two decimal places.) (a) Estimate the probability that a person who walks by the store will enter the store. 0.46 Correct: Your answer is correct. (b) Estimate the probability that a person who walks into the store will buy something. 0.41 Correct: Your answer is correct. (c) Estimate the probability that a person who walks by the store will come in and buy something. 0.19 Changed: Your submitted answer was incorrect. Your current answer has not been submitted. (d) Estimate the probability that a person who comes into the store will buy nothing. 0.27 Incorrect: Your answer is incorrect.

Respuesta :

Answer:

a) 0.46; b) 0.41; c) 0.19; d) 0.59

Step-by-step explanation:

For part a,

There were 121 people that walked by; out of these 56 entered the store.  This is an empirical probability of

56/121 ≈ 0.46

For part b,

There were 56 people that entered the store.  Of those, 23 bought something.  This is an empirical probability of

23/56 ≈ 0.41.

For part c,

We multiply the probability that someone walking by enters the store and the probability that someone entering the store buys something:

0.46(0.41) = 0.1886 ≈ 0.19

For part d,

Since the probability of someone entering the store buying something is 0.41, this means the probability that this person does not buy something is

1-0.41 = 0.59.

a) The probability that a person who walks by the store will enter the store is 0.46

b) The  probability that a person who walks into the store will buy something is 0.41

c) The probability that a person who walks by the store will come in and buy something is 0.19

d) The  probability that a person who comes into the store will buy nothing is 0.59

Calculation of the probabilities:

(a)

Since there were 121 people that walked by; out of these 56 entered the store.  So this represents the empirical probability

[tex]= 56\div 121[/tex]

≈ 0.46

(b)

Since there were 56 people that entered the store.  Of those, 23 bought something.

So, the probability is

[tex]= 23\div 56[/tex]

≈ 0.41.

(c)

The probability should be

= 0.46(0.41)

= 0.1886

≈ 0.19

(d) The probability should be

= 1-0.41

= 0.59.

learn more about the probability here: https://brainly.com/question/5680312