Answer: 3.16 units (Option C)
Step-by-step explanation:
The key to this problem is to use the distance formula, which is:
Distance = [tex]\sqrt{(x₁-x₂)²+(y₁-y₂)²}[/tex]
The first point, T = (x₁,y₁), and the second point, U = (x₂,y₂).
Plugging the two points into the equation, we get:
Distance = [tex]\sqrt{(1-2)^{2}+(-1-(-4))^{2} }[/tex]
The values within the parenthesis are subtracted:
Distance = [tex]\sqrt{(-1)^{2}+3^{2} }[/tex]
The values are then squared:
Distance = [tex]\sqrt{1+9}[/tex]
Finally, they are added together:
Distance = [tex]\sqrt{10}[/tex]
[tex]\sqrt{10}[/tex] can be approximated as 3.16, so the distance between the two points is 3.16 units.
The distance between the two points t and u is 3.16 units. The correct answer is (Option C).
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]
from the distance formula,
The first point, T = (x₁,y₁), and the second point, U = (x₂,y₂).
T = (1, -1)
U = (2, -4)
we get:
Distance =
[tex]D = \sqrt{(1-2)^2 + (-1-(-4))^2} \: \rm units.\\ \\D = \sqrt{(-1)^2 + (3)^2} \: \rm units.\\\\D = \sqrt{9 + 1}\\\\D = \sqrt{10}[/tex]
It can be approximated as 3.16,
Thus, the distance between the two points is 3.16 units. The correct answer is (Option C).
Learn more about the distance between two points here:
brainly.com/question/16410393
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