Respuesta :
Answer:
(C) [tex]\frac{d}{cos 65^{\circ}}[/tex].
Step-by-step explanation:
It is given that a right triangle PQR with an acute angle equal to 65° that is ∠QPR, PQ=d, PR=e and QR=f
Now, using trigonometry, we have
[tex]cos65^{\circ}=\frac{PQ}{PR}[/tex]
Substituting the given values, we get
[tex]cos 65^{\circ}=\frac{d}{e}[/tex]
[tex]e=\frac{d}{cos 65^{\circ}}[/tex]
Thus, the value of e is [tex]\frac{d}{cos 65^{\circ}}[/tex].
Hence, option (C) is correct.
