Answer:
1) f(n) =f(n-1) + 22
2) f(n)=f(n-1) + 21
3)f(n)=6*f(n-1)
Step-by-step explanation:
1) The first series is given as 11,33,55,77....
Also, f(1)=11
Now, f(n)=f(n-1) + 22
So, f(2)=f(1) + 22
=11 + 22
=33
f(3)=f(2) + 22
=33 + 22
=55
And so on.
2) The second series is given as -18,3,24,45....
Also, f(1)=-18
Now, f(n)=f(n-1) + 21
So, f(2)=f(1) + 21
=-18 + 21
=3
f(3)=f(2) + 21
=3 + 21
=24
And so on.
3) The third series is given as -18,-108,-648,-3888....
Also, f(1)=-18
Now, f(n)=6*f(n-1)
So, f(2)=6*f(1)
=6*(-18)
=-108
f(3)=6*f(2)
=6*(-108)
=-648
And so on.
