Answer:
The area of rectangle ABCD is 198 square inches.
Step-by-step explanation:
It is given that rectangle ABCD is congruent to rectangle HGJK.
The corresponding parts of congruent figure are congruent.
[tex]AD\cong HK[/tex] (CPCTC)
[tex]AD=HK=18[/tex] (Property of congruent)
In rectangle ABCD the length of the rectangle is 11 inches and width of the rectangle is 18 inches.
The area of a rectangle is
[tex]A=length\times width[/tex]
The area of rectangle ABCD is
[tex]A=AB\times AD[/tex]
[tex]A=11\times 18[/tex]
[tex]A=198[/tex]
Therefore the area of rectangle ABCD is 198 square inches.
