The equation of the line that is perpendicular to the given line and passes through the point (2, 6) is y = 6: Option D is correct.
The equation of a line in point-slope form is expressed as:
y - y0 = m(x-x0)
m is the slope of the line
(x0, y0) is any point on the line
- Since the given line is a horizontal line, the slope of the line is infinity
- The slope of the line perpendicular will be expressed as -1/∞ = 0
Get the required equation:
Recall that y - y0 = m(x-x0)
y - 6 = 0(x-2)
y - 6 = 0
y = 6
Hence the equation of the line that is perpendicular to the given line and passes through the point (2, 6) is y = 6
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