Respuesta :

DeanR

It's goofy to subtract perimeter and area; they're in different units.  We persist.

The area is [tex]s^2[/tex] and the perimeter is [tex]4s[/tex]. so the difference is

[tex]s^2 - 4s = (3 \sqrt{2})^2 - 4(3\sqrt{2}) = 18 - 12 \sqrt{2}[/tex]

Answer: choice A

Answer:

Answer: choice A

Step-by-step explanation:

The area is s^2 and the perimeter is 4s. so the difference is

s^2 - 4s = (3 \sqrt{2})^2 - 4(3\sqrt{2}) = 18 - 12 \sqrt{2}