Answer:
Option C: 11.7%
Step-by-step explanation:
The number of elements in sample space when a coin is flipped 10 times will be:
[tex]n(S) = 2^{10} \\= 1024[/tex]
Let A be the event that the tails appear 7 times:
Then,
[tex]C_{(n,k)}=\frac{n!}{(k!)(n-k)!} \\where\\n=population\\k=picks\\In our case, k =7\\and\\n=10\\C_{(10,7)}= \frac{10!}{(7!)(10-3)!}\\= 120\\So, \\P(A) = \frac{n(A)}{n(S)} \\P(A) = \frac{120}{1024} \\= 0.1171\\[/tex]
Converting into percentage:
[tex]P(A) = 0.1171*100=11.7%[/tex]
So, option C is correct ..
