If a probability distribution is 5/12, 1/6, 1/3, x, what is the value of x

The probabilities of all possible outcomes in a distribution must sum to 1.
[tex]\dfrac5{12}+\dfrac16+\dfrac13+x=1\implies x=\dfrac1{12}[/tex]
Answer:
1/12 C
Step-by-step explanation:
5/12
1/6=2/12
1/3=4/12
5/12-3=2/12
2/12+2=4/12
4/12-3= 1/12