Answer:
[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
Substitute x = 2 into both h(x) and f(x)
h(2) = [tex]\frac{1}{2-1}[/tex] = 1 ⇒ (h(2))² = 1
f(2) = 2 + 2 = 4
Hence
[tex]\frac{h(x)^2}{f(x)}[/tex] when x = 2
= [tex]\frac{1}{4}[/tex]
1/4 is the following function at x=2
A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and co domain, respectively. Initially, functions represented the idealized relationship between two changing quantities.
Given
Substituting x = 2 into both h(x) and f(x)
h(2) = 1(2-1) = 1 ⇒ (h(2))² = 1
f(2) = 2 + 2 = 4
Hence
h(x)²/f(x) when x = 2
=1/4
To know more about domain refer to :
https://brainly.com/question/11787743
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