In the formula d=/(x2-x1)^2+(y2-y1)^2 , how does each subtraction expression relate to the Pythagorean theorem?

Answer:
A
Step-by-step explanation:
I don't think you need this
Answer:
option A
Step-by-stevvp explanation:
In the formula [tex]d=\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
The formula is used to find the distance between two points
(x2-x1) gives the length of one leg
(y2-y1) gives the length of another leg
In a right angle triangle , Pythagorean theorem is [tex]c=\sqrt{a^2 + b^2}[/tex]
where a and b represents the sides of the triangle
Each subtraction expression in the formula represents the leg of the right angle triangle with the hypotenuse of length d