Respuesta :
1. Helium nucleus and electron/positron
- An [tex]\alpha[/tex] decay is a decay in which an [tex]\alpha[/tex] particle is produced.
An [tex]\alpha[/tex] particle consists of 2 protons and 2 neutrons: therefore, in an alpha-decay, the nucleus loses 2 units of atomic number (number of protons) and 2 units of mass number (sum of protons+neutrons).
The alpha-particle consists of 2 protons of 2 neutrons: so it corresponds to a nucleus of helium, which consists exactly of 2 protons and 2 neutrons.
- There are two types of [tex]\beta[/tex] decay:
-- In the [tex]\beta^-[/tex] decay, a neutron decays into a proton emitting a fast-moving electron and an anti-neutrino:
[tex]n \rightarrow p + e^- + \bar{\nu}[/tex]
and the [tex]\beta[/tex] particle in this case is the electron
-- In the [tex]\beta^+[/tex] decay, a proton decays into a neutron, emitting a fast-moving positron and a neutrino:
[tex]p \rightarrow n + e^+ + \nu[/tex]
and the [tex]\beta[/tex] particle in this case is the positron.
2) Gamma ray
A [tex]\gamma[/tex] decay occurs when an unstable (excited state) nucleus decays into a more stable state. In this case, there are no changes in the structure of the nucleus, but energy is released in the form of a photon:
[tex]X^* \rightarrow X + \gamma[/tex]
where the wavelength of this photon usually falls in the part of the electromagnetic spectrum corresponding to the gamma ray region.
So, the [tex]\gamma[/tex] ray is commonly known as gamma radiation.
3)
The sign of the three forms of radiation are the following:
- [tex]\alpha[/tex] particle: it consists of 2 protons (each of them carrying a positive charge of +e) and 2 neutrons (uncharged), so the total charge is
Q = +e +e = +2e
- [tex]\beta[/tex] particle: in case of [tex]\beta^-[/tex] radiation, the particle is an electron, so it carries a charge of
Q = -e
in case of [tex]\beta^+[/tex] radiation, the particle is a positron, so it carries a charge of
Q = +e
- [tex]\gamma[/tex] radiation: the [tex]\gamma[/tex] radiation consists of a photon, and the photon has no charge, so the charge in this case is
Q = 0