Answer:
Step-by-step explanation:
[tex]f(x)=2x;\ g(x)=?\\\\(g\circ f)(x)=6x+2=3(2x)+2=3\bigg(f(x)\bigg)+2\to g(x)=3x+2\\\\Check:\\\\f(x)=2x,\ g(x)=3x+2\\\\(g\circ f)(x)\to\text{instead of x in g (x), put}\ 2x:\\\\(g\circ f)(x)=3(2x)+2=6x+2\qquad\bold{CORRECT :)}[/tex]