Answer:
The system has no solution.
Step-by-step explanation:
We have two equations:
1st: x+4y=10
2nd: 3x+12y=20
Write the two equations in slope-intercept form:
First equation:
4y=-x+10
[tex]y=-\frac{1}{4}x+\frac{5}{2}[/tex]
Second equation:
3x+12y=20
12y=-3x+20
Divide through by 12
[tex]y=-\frac{1}{4}x+\frac{5}{3}[/tex]
The two equations have the same slope but different y-intercepts.
The two equations are parallel and will never meet.
Therefore the system has no solution.
