Answer:
The surface area is [tex]404.8\ in^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the figure is equal to
[tex]SA=2B+PL[/tex]
where
B is the area of the trapezoidal face
P is the perimeter of the trapezoidal face
L is the length of the figure
Find the area of B
[tex]B=\frac{1}{2}(15+5)8\\ \\B=80\ in^{2}[/tex]
Find the perimeter P
[tex]P=(8+5+12.8+15)=40.8\ in[/tex]
we have
[tex]L=6\ in[/tex]
substitute the values
[tex]SA=2(80)+(40.8)(6)=404.8\ in^{2}[/tex]
