Answer:
The force on the faster cart is 3 times the force on the slower cart
Explanation:
The relationship between force exerted on each cart (F), mass of the cart (m) and acceleration (a) is given by Newton's second law:
[tex]F=ma[/tex]
For cart A, we have
[tex]F_A = m a_A[/tex] (1)
For cart B, we have
[tex]F_B = m a_B[/tex] (2)
the problem says that the acceleration of one cart is 3 times the acceleration of the other one, so
[tex]a_B = 3 a_A[/tex]
Substituting into eq.(2):
[tex]F_B = m(3 a_A)=3 (m a_A)[/tex]
So, if we divide (2) by (1), we find the ratio between the two forces:
[tex]\frac{F_B}{F_A}=3[/tex]
so, the force on cart B is 3 times larger the force on cart A.