Answer:
[tex]x=\frac{3}{2}[/tex]
Step-by-step explanation:
When we don't have any base with "log", we assume it to have base 10.
Using the property Log M + Log N = Log(M*N), we can write:
Log (2x-1) + Log 5 = 1
Log ((2x-1)(5)) = 1
We can turn this into exponential form using [tex]Log_{a} b=x\\a^x=b[/tex]
Thus,
[tex]10^1=(2x-1)(5)\\10=10x-5\\10+5=10x\\15=10x\\x=\frac{15}{10}=\frac{3}{2}[/tex]