Answer:
[tex]x_1=1.23\\x_2=-0.40[/tex]
Step-by-step explanation:
Given a quadratic equation in the form [tex]ax^2+bx+c=0[/tex], you can use the Quadratic formula to solve it. This is:
[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]
Then, you need to subtract [tex]5x[/tex] from both sides of the equation given:
[tex]5x-5x=6x^2-3-5x\\0=6x^2-5x-3[/tex]
You can identify that:
[tex]a=6\\b=-5\\c=-3[/tex]
Then, substituting values into the Quadratic formula, you get:
[tex]x=\frac{-(-5)\±\sqrt{(-5)^2-4(6)(-3)}}{2(6)}[/tex]
[tex]x_1=1.23\\x_2=-0.40[/tex]
Answer: B is the correct answer
Step-by-step explanation:
