Answer: Second option.
Step-by-step explanation:
The square root of a number "x" is a number "b" that multiplied by itself is "x":
[tex]b*b=x[/tex]
We know that the square root of 16 is 4 ([tex]\sqrt{16}=4[/tex]) because:
[tex]4*4=16[/tex]
Then [tex]\sqrt{13}[/tex] should be less than 4.
We know that the square root of 9 is 3 ([tex]\sqrt{9}=3[/tex]) because:
[tex]3*3=9[/tex]
Then [tex]\sqrt{13}[/tex] should be greater than 3.
Therefore, the value of [tex]\sqrt{13}[/tex] is between 3 and 4.
This matches with the second option.
