Which equation has an a-value of 1, a b-value of -3, and a c-value of -5 ?

Answer: The correct option is
(A) [tex]0=-3x-5+x^2.[/tex]
Step-by-step explanation: We are given to select the correct quadratic equation that has an a-value of 1, b-value of -3 and c-value of -5.
We know that
a general quadratic equation is of the following form :
[tex]ax^2+bx+c=0,~~a\neq0,[/tex]
where a is the coefficient of x²,
b is the coefficient of x
and
c is the constant term.
For the given equation, we get
the coefficient of x², a = 1,
the coefficient of x, b = -3
and
the constant term, c = -5.
Therefore, the required equation is
[tex]1\times x^2+(-3)\times x+(-5)=0\\\\\Rightarrow 0=-3x-5+x^2.[/tex]
Thus, (A) is the correct option.