Respuesta :
Answer:
- $ 163.54
Explanation:
1) Write the model for the volume and base area of the rectangular sotorage container:
- Base area, B = base length × base width
base width, w = x
base length, l = 2x
B = (2x) (x) = 2x²
- Volume, V = base area × height = 10 m³
height = h
V = 2x² h = 10 ⇒ h = 10 / (2x²)
2) Total area, A
- Base, B = 2x²
- Side 1, S₁
S₁ = (x) . (h) = (x) . 10 / (2x²) = 10 / (2x) = 5 / x
- Side 2, S₂
S₂ = S₁ = 5 / x
- Side 3, S₃
S₃ = (2x) . (h) = (2x) . 10 / (2x²) = 10 / x
- Side 4, S₄
S₄ = S₃ = 10 / x
3) Cost
- Material for the base:
$ 10 (2x²) = 20x²
- Material for the sides
$6 (S₁ + S₂ + S₃ + S₄) = 6 (5/x + 5/x + 10/x + 10/x ) = 6 ( 30/x) = 180/x
- Total cost = 20x² + 180 / x
4) Cheapest container
Minimum cost ⇒ find the minimum of the function 20x² + 180 / x, which formally is done by derivating the function and making the derivative equal to zero.
- Derivative: (20x² + 180 / x)' = 40x - 180 / x² = 0
Solve to find the value of x that makes the first derivative equal to zero:
- 40x - 180 / x² = 0
- Assume x ≠ 0 and multiply by x² : 40x³ - 180 = 0
- Add 180 to both sides: 40x³ = 180
- Divide by 40: x³ = 4.5
- Cubic root: x = 1.65
Replace x = 1.65 in the equations of costs to find the minimum cost:
- 20x² + 180 / x = 20 (1.65)² + 180 / (1.65) = 163.54
That is the final answer, already rounded to the nearest cent: $163.54