Respuesta :
Answer:
D = 16
Step-by-step explanation:
[tex]-x^2+2x=-3\qquad\text{add 3 to both sides}\\\\-x^2+2x+3=0\\\\a=-1,\ b=2,\ c=3\\\\\text{Substitute to}\ D=b^2-4ac:\\\\D=2^2-4(-1)(3)=4+12=16[/tex]
Answer:
Discriminant = 16
Step-by-step explanation:
We have the following expression: -3 = -x^2 + 2x
Organizing the expression, we have: x^2 - 2x -3 = 0
We know that for an equation of the type: ax^2 + bx + c = 0, the discriminant is: b^2-4ac
From our equation we know that a=1, b=-2, and c=-3.
Then Discriminant = (-2)^2 - 4(1)(-3)
Discriminant = 4 +12 = 16