What is the surface area of the regular pyramid below

[tex]
S=14\times14+4(\frac{14}{2}\times18) \\
S=196+4(7\times18) \\
S=196+4\times126 \\
S=196+504 \\
S=\boxed{700}
[/tex]
Answer:
B. [tex]700\text{ inches}^2[/tex].
Step-by-step explanation:
We have been given an image of a pyramid. We are asked to find the total surface area of the given pyramid.
[tex]\text{Surface area of pyramid}=A+\frac{1}{2}*ps[/tex], where,
A = Area of base of pyramid.
p = Perimeter of base,
s = Slant height,
Upon substituting our given values, we will get:
[tex]\text{Surface area of pyramid}=14^2+\frac{1}{2}*4*14*18[/tex]
[tex]\text{Surface area of pyramid}=196+2*14*18[/tex]
[tex]\text{Surface area of pyramid}=196+504[/tex]
[tex]\text{Surface area of pyramid}=700[/tex]
Therefore, the total surface area of given pyramid is 700 square inches and option B is the correct choice.