Answer:
A. Shorter in wavelength and higher in energy
Explanation:
The peak wavelength of a star can be found by using Wien's displacement law:
[tex]\lambda=\frac{b}{T}[/tex]
where
b is the Wien's displacement constant
T is the surface temperature of the star
From the equation, we see that the peak wavelength [tex]\lambda[/tex] is inversely proportional to the temperature: therefore, a star which is hotter then the sun (greater T) will have shorter wavelength.
Moreover, the energy of the emitted radiation is inversely proportional to the wavelength:
[tex]E=\frac{hc}{\lambda}[/tex]
where h is the Planck constant, c is the speed of light. Therefore, shorter wavelength means higher energy.
So, the correct answer is
A. Shorter in wavelength and higher in energy
