Answer:
Explanation:
molarity is moles of solute/L solution
5.5 g 1 moles Kl 1000 mL
_____ * __________ * ________ = 0.22088 M
150 ml of solution 166 grams 1 L
(39 grams K+ 127 grams I) ^
Answer:
[tex]\boxed{\text{0.22 mol/L}}[/tex]
Explanation:
[tex]\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\\text{c} = \dfrac{n}{V}[/tex]
1. Convert grams to moles.
[tex]\text{Moles KI = 5.5 g KI} \times \dfrac{\text{1 mol KI}}{\text{166.0 g KI}} = \text{0.0331 mol KI}[/tex]
2. Convert millilitres to litres
[tex]\text{V = 150 mL} \times \dfrac{\text{1 L}}{\text{1000 mL}} = \text{0.1500 L}[/tex]
3. Calculate the molar concentration
[tex]c = \dfrac{\text{0.0331 mol}}{\text{0.1500 L}} = \text{0.22 mol/L}[/tex]
The molar concentration of KI is [tex]\boxed{\textbf{0.22 mol/L}}[/tex].
