A wall map is 45 cm high and 27 cm wide. Ashley wants to proportionately shrink it so its height is 12 cm. How wide would it be then?

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calculista calculista · Answer 1 · 2019-05-16T03:47:10+02:00

Answer:

[tex]x=7\frac{1}{5}\ cm[/tex]

Step-by-step explanation:

Let

x-------> the proportional wide

we know that

Using proportion

[tex]\frac{45}{27}=\frac{12}{x}\\ \\x=27*12/45\\ \\x= 7.2\ cm[/tex]

Convert to mixed number

[tex]7.2\ cm=7+0.2=7+\frac{2}{10}=7+\frac{1}{5}=7\frac{1}{5}\ cm[/tex]

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JeanaShupp JeanaShupp · Answer 2 · 2019-06-10T15:45:06+02:00

Answer: [tex] x=\ 7\dfrac{1}{5}\ cm[/tex]

Step-by-step explanation:

If there is proportional relation between two variables x and y , then we have the following equation:

[tex]\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}[/tex]

Given: A wall map is 45 cm high and 27 cm wide.

Ashley wants to proportionately shrink it so its height is 12 cm.

Let x be the width of the shrunk map.

Then by using above formula we have,

[tex]\dfrac{x}{27}=\dfrac{12}{45}\\\\\Rightarrow\ x=27\times\dfrac{12}{45}\\\\\Rightarrow x=\ 7\dfrac{1}{5}\ cm[/tex]