Find the length of the radius of a circle whose center is at (12, 5 ), and one point on the circle is ( -6, -18 ). Round to the nearest hundredth of the units.

Respuesta :

Hello!

The answer is:

The radius of the circle is 29.21 units.

Why?

To solve the problem, we need to remember that the radius of a circle is the distance from its center to any point of the circle.

We can use the following equation to calculate the distance between the center and the given point:

[tex]distance=radius=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2} }[/tex]

So, we are given the information:

[tex]Center(12,5)\\Point(-6,-18)[/tex]

Where,

[tex]x_1=12\\y_1=5\\x_2=-6\\y_2=-18[/tex]

Now, substituting and calculating, we have:

[tex]radius=\sqrt{((-6)-(12))^{2}+((-18)-(5)^{2}}\\\\radius=\sqrt{(-18)^{2}+(-23)^{2}}=\sqrt{324+529}=\sqrt{853}=29.21units[/tex]

Hence, we have that the radius of the circle is 29.21 units.

Have a nice day!

Answer:

AB =  29.23

Step-by-step explanation:

Points to remember

Distance formula

Distance between two points (x₁, y₁) and (x₂, y₂) is given by

Distance = √[(x₂- x₁)² + (y₂ - y₁)²]

To find the radius

Center = (12, 5) and point on the circle = (-6, -18)

Radius = √[(x₂- x₁)² + (y₂ - y₁)²]

  =  √[(12 - - 6)² + (5 -  -18)²]

  = √[(12 + 6)² + (5 +18)²]

  =√[18² + 23²] = √[324 +529 ]  =  29.23