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Based on the tree diagram below, what is the probability that a student doesn't have lice, given that the student tested negative? Round your answer to the nearest tenth of a percent.
A. 97.6%
B. 99.4%
C. 96.4%
D. 98.6%

Respuesta :

annabellesalter

Answer:

Option D (APEX)

Step-by-step explanation:

L= Student has lice

NL= Student has no lice

PT=Test Shows positive

NT=Test Shows negative

P([tex]\frac{NT}{NL}[/tex]) =0.7708 (Probability that a student has no lice and the test shows negative)

P([tex]\frac{NT}{L}[/tex]) = 0.0108 ( Probability that a student has lice and the test shows negative)

  1. [tex]P\frac{NT}{NL}[/tex] = [tex]\frac{P\frac{NT}{NL} }{P\frac{NT}{NL} +P\frac{NT}{L} }[/tex]
  2. [tex]\frac{0.7708}{0.7708+00108}[/tex]
  3. [tex]\frac{0.7708}{0.7816}[/tex]
  4. 0.98618219 (Simplify)

Terms Of Percentages

0.98618219 × 100

=98.6

Therefore your answer is 98.6% (Option D)

APEX

Answer: D

Step-by-step explanation:

apec

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