Answer:
(A) 180
Step-by-step explanation:
We have to treat those player selections as independent events, since one doesn't influence the other (the fact you chose Joe as a guard, shouldn't have an influence on who'll pick as center, unless there's bad blood between some players... but that's a whole other story).
So, how many ways to pick 2 guards from a selection of 4? The order doesn't seem to matter here, since they don't specify for example that Joe can only play on the left side). So, it's a pure combination calculation:
[tex]C(4,2) = \frac{4!}{2! * (4 - 2)!} = \frac{24}{2 * 2} = 6[/tex]
C(4,2) = 6.
How many ways to pick the 2 forwards from a group of 5? Using the same calculation, we get:
C(5,2) = 10.
And of course, the coach has 3 ways to pick a center player from 3.
Then we multiply the possible ways to pick guards, forwards and center...
6 * 10 * 3 = 180 ways.
