The probability that the selected marble is Green for the considered case is given by: Option B: 1/3
Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.
Then, suppose we want to find the probability of an event E.
Then, its probability is given as
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}[/tex]
where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.
Given that:
To find: P(selected marble is green)
Take:
E = event that a marble selected at random is green.
Numbre of cases in which E can be done is 3 (as there are 3 green marbles).
Number of total cases = 3+3+3 = 9 (total 9 marbles, each can come as an outcome).
Thus, we get:
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)} = \dfrac{3}{9} = 1/3[/tex]
Thus, the probability that the selected marble is Green for the considered case is given by: Option B: 1/3
Learn more about probability here:
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